Question

calculeaza masa solutiei de hcl de 10% necesar pentru a reactiona cu 171g de solutie de ba(oh)2 de 20%

Answer 1

2HCl+Ba(OH)2=BaCl2+2H2O
c=md/ms*100
md=c*ms/100=20*171/100=34,2 g Ba(OH)2
M HCl=AH+ACl=1+35,5=36,5 g/mol
M  Ba(OH)2=ABa+2AO+2AH=137+2*16+2*1=171g/mol
2*36,5 gHCl..................171g Ba(OH)2
Xg................................34,2
x=2*36,5*34,2/171=14,6g HCl
c=md/ms*100
ms=md*100/c=14,6*100/10=146g HCl