Question

Calculeaza.Ofer 100 de puncte

Answer 1

Asta e rezolvarea ce nu intelegi îmi spui

Answer 2

$[2,5+2,(6)-\frac{7}{12} ]:\frac{11}{4} +\frac{4}{3} =\\(\frac{25}{10} +\frac{26-2}{9} -\frac{7}{12} ):\frac{11}{4} +\frac{4}{3} =\\(\frac{5}{2} +\frac{24}{9} -\frac{7}{12} ):\frac{11}{4} +\frac{4}{3} =\\(\frac{5}{2}+\frac{8}{3} -\frac{7}{12} ):\frac{11}{4} +\frac{4}{3} =\\(\frac{5*6}{12} +\frac{8*4}{12} -\frac{7}{12} ):\frac{11}{4} +\frac{4}{3} =\\(\frac{30+32-7}{12} ):\frac{11}{4} +\frac{4}{3} =\\\frac{55}{12} :\frac{11}{4} +\frac{4}{3} =\\\frac{55}{12} *\frac{4}{11} +\frac{4}{3} =$

$\frac{5}{3} +\frac{4}{3}=\\\frac{9}{3} =3$

_________________________________

$[(\frac{2}{5} +\frac{1}{10} )*\frac{1}{3} ]^2-\frac{1}{4} =\\=[(\frac{4}{10} +\frac{1}{10} )*\frac{1}{3} ]^2-\frac{1}{4} =\\(\frac{5}{10} *\frac{1}{3} )^2-\frac{1}{4} =\\(\frac{1}{2} *\frac{1}{3} )^2-\frac{1}{4} =\\(\frac{1}{6} )^2-\frac{1}{4} =\\\frac{1}{36} -\frac{1}{4} =\\\frac{1}{36} -\frac{9}{36} =\\-\frac{8}{36} =-\frac{2}{9}$

______________________________

$(16^{-2}*8^{-3})^2*32^7=\\((2^4)^{-2}*(2^3)^{-3})^2*(2^5)^7=\\(2^{-8}*2^{-9})^2*2^{35}=\\(2^{-8-9})^2*2^{35}=\\(2^{-17})^2*2^{35}=\\2^{-34}*2^{35}=\\2^{-34+35}=2^1=2$