Question

calculează prin metoda comparatiei: 14C+10F=618 LEI 7C+24F=632LEI 1C, 1F =? EX. DOI 3C+5P = 2300 GRAME. 4C+2P= 1200 GRAME. 1C,1P = ? EX. TREI. 4C+8P = 48 LEI. 7C+3P= 29 LEI. 1C, 1P = ?

Answer 1

Ex 1
14C...10F...618 lei
7C....24F...632 lei inmultim cu 2
Vom avea urmatoarele relatii:
14C...10F...618 lei
14C...48F...1264 lei
48-10=38(F in plus)
1264-618=646(lei in plus pt 38 F)
646:38=17(F)
10×17=170(10 F)
618-170=448(14 C)
448:14=32(C)

Ex 2
3C...5P...2300 grame inmultim cu 4
4C...2P...1200 grame inmultim cu 3
Obtinem:
12C...20P...9200 grame
12C...6P....3600 grame
20-6=14(P in plus)
9200-3600=5600(grame in plus pt 14 P)
5600:14=400(grame 1 P)
5×400=2000(grame pt 5 P)
2300-2000=300(grame 3C)
300:3=100(grame 1 C)

Ex 3
4C ...8 P....48 lei inmultim cu 7
7C ...3 P....29 lei inmultim cu 4
Obtinem relatiile:
28 C....56 P...336 lei
28 C....12 P...116 lei
56-12=44( P in plus)
336-116=220(lei in plus pentru 44 P)
220:44=5(lei 1 P)
5×56=280(lei pentru 56 P)
336-280=56(lei pentru 28 C)
56:28=2(lei 1 C)