Question

calculeaza raportul de atomi si raportul de masa pentru Mg(NO3)2, HClO4, KClO3, Ca(OH)2, SiCl4, C2H5OH

Answer 1

Mg(NO3)2

raport atomic=r.a.=1Mg:2N:6O=1:2:6
raport de masa=r.m.=AMg:2AN:6AO
                                =24:2.14:6.16
                                =24:28:96        se simplifica cu 4
                               =6: 7:24




HClO4

r.a.=1H:1Cl:4O =1:1:4

r.m.=AH:ACl:4AO=1:35,5:4.16=1:35,5:64


KClO3

r.a.=1K:1Cl:3O=1:1:3

r.m.=AK:ACl:3AO=39:35,5:3.16=39:35,5:48

Ca(OH)2

r.a.=1Ca:2O:2H=1:2:2

r.m.=ACa:2AO:2AH=40:2.16:2=40:32:2=20:16:1


SiCl4

r.A.=1Si:4Cl=1:4
r.m.=ASi:4ACl=28:4.35,5=28:142=14:71



C2H5OH

r.a.=2C:6H:1O=2:6:1

r.m.=2AC:6AH:AO=2.12:6:16=24:6:16=12:3:8