Question

calculează,respectand regulile învățate:[2×(1+29)-59]×9. ;6×[(60-24):6+(30-30:6)] ;[120-(4×20)×3:(54:9)]÷8[38+(106-88)÷9]÷(56÷7)

Answer 1

[2×(1+29)-59]×9=
(2×30-59)×9=
(60-59)×9=
1×9=
9

6×[(60-24):6+(30-30:6)]=
6×[36:6+(30-5)]=
6×(6+25)=
6×31=
186

[120-(4×20)×3:(54:9)]÷8=
(120-80×3:6)÷8=
(120-240:6)÷8=
(120-40)÷8=
80÷8=
10


[38+(106-88)÷9]÷(56÷7)=
(38+18÷9)÷8=
(38+2)÷8=
40÷8=
5

Answer 2

[2×(1+29)-59]×9
=(2×30-59)×9
=(60-59)×9
=1×9
=9

6×[(60-24):6+(30-30:6)]
=6×[36:6+(30-5)]
=6×(6+25)
=6×31
=186

[120-(4×20)×3:(54:9)]:8
=(120-80×3:6):8
=(120-240:6):8
=(120-40):8
=80:8
=10

[38+(106-88):9]:(56:7)
=(38+18:9):8
=(38+2):8
=40:8
=5