Question

Calculează respectând regulile pe care le introduc parantezele in calcule.a.125:5+(13+64:2). b.(37-18:2):7+108:2. c.6×9:[6-(13-18:2)] d.[(9-6)×(8+9)]+100:(4+6) .e.5×[3600:30-81:(54:6)]. f.128:4+[2×(2222:22-22:22)]:10.g.36:9+4×[20+6×(100:4-42:2)].h.126-[(63×2:6+109)×(75:25+21:3)]:10 va rog ajutati-ma urgent dau coroniță

Answer 1

a) 125:5+(13+64:2)=125:5+(13+32)=
=25+45=70
b) (37-18:2):7+108:2=(37-9):7+54=
=28:7+54=4+54=58
c) 6×9:[6-(13-18:2)]=54:[6-(13-9)]=
=54:(6-4)=54:2=27
d)[(9-6)×(8+9)]+100:(4+6)=(3×17)+100:10=
=51+10=61
e) 5×[3600:30-81:(54:6)]=
=5×(3600:30-81:9)=5×(120-9)=5×111=555
f)128:4+[2×(2222:22-22:22)]:10=
=32+[2×(101-1)]:10=32+(2×100):10=
=32+200:10=32+20=52
g) 36:9+4×[20+6×(100:4-42:2)]=
=4+4×[(20+6×(25-21)]=4+4×(20+6×4)=
=4+4×(20+24)=4+4×44=4+176=180
h)126-[(63×2:6+109)×(75:25+21:3)]:10=
=126-[(126:6+109)×(3+7)]:10=
=126-[(21+109)×10]:10
=126-(130×10):10=126-1300:10=126-130=-4