Question

calculeaza si afla numarul necunoscut:a)*(136+a)-425=565; (512+413-159)-a; (513+a)+347=960:b)a-(512-83)=450;1200+(250-a)=1400;a×4=3948=3932

Answer 1

(136+a)-426=565
136+a=565+426
136+a=991
a= 991-136
a=855
(512+413-159)-a acest exercitiu nu cred ca este intreg
(513+a)+347=960
(513+a)= 960-347
513+a= 613
a= 613-513
a= 100
b) a-(512-83)= 450
a- 429= 450
a= 450+429
a=879

1200+(250-a)=1400
(250-a)= 1400-1200
259-a=200
a=259-200
a= 59

a×4=3948
a=3948:4
a=987

a×4= 3932
a=3932:4
a=983