Question

calculează te rog repede
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Answer 1

Răspuns:

A. 2^2015(2^2-2^1-1):2^2:2^2008+1*1=

2^2015*1:2^2:2^2008+1=2^5=32

B(1+27^1350:9^2000):2^100=

(1+3^4050:3^4000):2^100=

1+3^50:2^100

C2^6:2^6+3^4:(64-36-1)=

2^0+3^4:27=1+3^4:3^3=1+3^1=1+3=4