Question

Calculează:
$\binom{7}{9} ^{0} \\ \\ \binom{31}{51} ^{1} \\ \\ \binom{2^{5} \times 3 }{16 \times 6}^{50}$
Vă rog frumos
Dau coroană ​

Answer 1

Răspuns: Ai mai jos rezolvarea

Explicație pas cu pas:

Buna!

$\large\bf \bigg(\dfrac{7}{9} \bigg)^{0}=\dfrac{7^{0}}{9^{0}}=\dfrac{1}{1}=1$

$\bf$

$\large\bf \bigg(\dfrac{31}{51} \bigg)^{1}=\dfrac{31^{1}}{51^{1}}=\dfrac{31}{51}$

$\bf ~~~$

$\large\bf \bigg(\dfrac{2^{5}}{16}\cdot \dfrac{3}{6} \bigg)^{50}=\bigg(\dfrac{2^{5}}{2^{4}}\cdot \dfrac{\not3}{\not 6} \bigg)^{50}=\bigg(\dfrac{\not2^{5}}{\not2^{4}}\cdot \dfrac{1}{2} \bigg)^{50}=\bigg(\dfrac{2}{1}\cdot \dfrac{1}{2} \bigg)^{50}=\bigg(\dfrac{\not2}{\not2} \bigg)^{50}=1^{50}=\boxed{\Large\bf 1}$

PS: Daca esti pe telefon, te rog sa glisezi spre dreapta pentru a vedea rezolvarea completa

==pav38==