Question

Calculeaza Vaer, cu 20% O2, masurat in conditii normale, necesar arderii a 2m^{3} [/tex] acetilena.

Answer 1

V C2H2=2m³=2000 dm³=2000 l
20% O2, c.n.

C2H2+ 5/2O2----------> 2CO2 + H2O + Q

V C2H2=N C2H2*22,4
N C2H2=V C2H2/22,4
N C2H2=2000/22,4
N C2H2=89,28 mol

1 mol C2H2.................5/2 mol O2
89,28 mol C2H2......... N O2
N O2=89,28*5/2
N O2=223,2 mol
V O2=N O2*22,4
V O2=223,2*22,4
V O2=4999,68 l

V aer..................100%
4999,68 l............20%
V aer=4999,68*100/20=4999,68*5
V aer=24998,4 l
V aer=25 m³