Question

calculeaza volumul (c.n.) a substantei H2, O2, SO2. Daca masa fiecareia este egala cu 32g

Answer 1

m H2 = 32g

n = m/M => 32/2 = 16 moli H2

V = 22.4*16= 358.4 l H2

m O2 = 32 g

n= m/M = 32/32 = 1 mol O2

V= 22.4*1=22.4 l O2

m SO2= 32 g

n=m/M = 32/64= 0.5 moli SO2

V = 22.4*0.5=11.2 l SO2