Question

Calculeaza volumul de acetilena (c.n.) necesar obtinerii unei tone de poliacetat de vinil cu un randament global de 75%.

Answer 1

1t=1000kg


26kg.........2kg..........28kg
HC≡CH + H-H --> H2C=CH2
x=302.315kg.....y=.23.255kg....325.57kg

n(eta)=mp/mt*100==>mt=mp*100/n=302.315*100/75=403kg

n=m/M=403/26=15.5kmoli
n=V/Vmolar==>V=n*Vm=15.5*22.4=347.2m3 C2H2 (acetilena)

56kg.................120kg.............32kg..............172kg...........................36kg
2H2C=CH2 + 2CH3-COOH + O2 --> 2(CH3-CO-O)-CH=CH2 + 2H2O
x=325.57kg....y=697.67kg....z=186kg..............1000kg.............w=209.3kg

86kg................................................86kg
nCH2=CH-(O-CO-CH3) --> [-CH2-CH-(O-CO-CH3-]n 
1000kg..........................................1000kg

Mpoliacetat,acetat=86kg/kmoli
MC2H2=26kg/kmoli
MC2H4=28kg/kmoli