Question

Calculeaza volumul de H2,(c.n) care se degaja la interactiunea Zn cu masa de 6.5g si a sol HCl cu masa de 73g si partea de masa HCl egala cu 20 procente

Answer 1

65g...73g.....136g...2g
Zn + 2HCl= ZnCl2 + H2
6.5g...14.6g...x=20.794g..y=0.3g

1mol Zn......2 moli HCl....1mol ZnCl2....1mol H2
0.1moli.......0.4moli..........x=0.166moli....y=0.166moli H2

n=V/Vmolar==>V=n*Vmolar=0.166*22.4=3.73 L H2

n=m/M=6.5/65=0.1 moli Zn

Cp=md/ms*100==>md=Cp*ms/100=73*20/100=14.6g HCl

n=m/M=14.6/36.5=0.4 moli HCl