Question

Calculeaza volumul hidrogenului necesar pentru hidrogenarea a 100g de trioleoil-gliceron?

Answer 1

M trioleina = 885.4 g/mol
m trioleina = 100 g
n trioleina = 100/885.4 =0.113 mol trioleinA

1mol trioleina ......... 3 mol H2
0.113 mol trioleina....a mol H2

a= 0.113 x 3/1=0.339 mol  H2
V H2 = n H2 * 22.4 l/mol => V H2 = 0.339 * 22.4 = 7.59 L H2