Question

calculează x+y+z+2,stiind ca: a)x=13si y+z=32
b)y=57si z+x=131
c)z=351si y+x=3867

Answer 1

a) x=13 si y+z=32
$a) \\ 13 + 32 + 2 = 47$

b) y=57 si z+x=131
$b) \\ 131 + 57 + 2 = 190$

c) z=351 si x+y=3867
$c) \\ 351 + 3867+2 = 4220$

Answer 2

a) x = 13
y+z= 32
x+y+z+2= 13+32+2 = 47


b) y = 57
z+x = 131
y+z+x+2 = 57+131+2 = 188+2 = 190

c) z = 351
y+x = 3867
y+z+x+2 = 351 + 3867 + 2 = 4218 + 2 = 4220