Question

căldura degajata la arderea a 12,5 g etena

Answer 1

1 mol etena degaja ΔrH = -1389 kJ (din date termodinamice)

niu = masa / miu

miu C2H4 = 24+4 = 28 g/mol

=> niu = 12,5/28 = 0,45 moli etena

1 mol .................. -1389 Kj

0,45 moli .............. a  = -620 Kj