Question

caluleaza a+b+c stiind ca a=3×b c=2×a a<c cu 96.​

Answer 1

Răspuns:

a+b+c=?

a=3 * b =>a=3b

c=2a =>c=6b

a=c-96 =>c=96+a =>c=96+3b

96+3b=6b

3b=96 =>b=96/3 =>b=32

a=3b=>3*32 =>a=96

c=96+3b =>96+96 =>c=192

a+b+c=96+32+192 = 128+192=320

Answer 2

$\it \left.\begin{aligned} \it c=2a\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \rule{1}{0.1}\\ \\ \it a<c\ cu\ 96 \Rightarrow c>a\ cu\ 96 \Rightarrow c=a+96 \end{aligned}\right\} \Rightarrow a=96,\ \ c=2\cdot96=192\\ \\ \\ a=3b \Rightarrow 96=3b|_{:3} \Rightarrow b=32\\ \\ \\ a+b+c=96+192+32=320$