Question

Cantitatea de acid etandioic ce se poate oxida cu 0,5L solutie acida de KMnO4 1M este:

Answer 1

HOOC-COOH + 5[O]-->2CO2+H2O

2KMnO4+3H2SO4-->K2SO4+2MnSO4+3H2O+5[O]

Concentratia molara=n/V=> n=V*CM=0,5*1=0,5 moli KMnO4

2 moli KMnO4.......1 mol HOOC-COOH
0,5 moli KMnO4.....x==> x=0,25 moli HOOC-COOH
M C2H2O4=90 g/mol
m=n*M=90*0,25=22,5 g HOOC-COOH

Acum mi-am amintit, imi cer scuze.