Question

Care e suma numerelor care impartite la 7 dau catul 5

Answer 1

Răspuns:

x:7=5=>x=7·5=>x=35

dar poate fi si un rest

stim ca R < I

R = 0,1,2,3,4,5,6

x:7=5rest1=>x=7·5+1=>x=36

x:7=5rest2=>x=7·5+2=>x=37

.

x:7=5rest6=>x=7·5+6=>x=41

nr sunt 35,36,37,38,39,40,41

S=35+36+37+38+39+40+41=266

Answer 2

a : 7 = 5 rest 0

a = 5 × 7 + 0

a = 35 + 0

a = 35

b : 7 = 5 rest 1

b = 5 × 7 + 1

b = 35 + 1

b = 36

c : 7 = 5 rest 2

c = 5 × 7 + 2

c = 35 + 2

c = 37

d : 7 = 5 rest 3

d = 5 × 7 + 3

d = 35 + 3

d = 38

e : 7 = 5 rest 4

e = 5 × 7 + 4

e = 35 + 4

e = 39

f : 7 = 5 rest 5

f = 5 × 7 + 5

f = 35 + 5

f = 40

g : 7 = 5 rest 6

g = 5 × 7 + 6

g = 35 + 6

g = 41

35 + 36 + 37 + 38 + 39 + 40 + 41 =

71 + 37 + 38 + 39 + 40 + 41 =

108 + 38 + 39 + 40 + 41 =

146 + 39 + 40 + 41 =

185 + 40 + 41 =

225 + 41 = 266