Question

Care este aminoacidul care contine 32% C ; 6,66 %H si 18,66 %N in molecula sa si are masa moleculara egala cu 75 ?

Answer 1

Aminoacidul conține:

32% C , 6.66% H , 18.66% N   (⇒57.32%)

100% - 57.32% = 42.68 % O

$C: \frac{32}{12}=2.66\ \ |:1.33\implies C:2\\\\H: \frac{6.66}{1}=6.66\ |:1.33\implies H:5\\\\N:\frac{18.66}{14}=1.33\ |:1.33\implies N:1\\\\O:\frac{42.68}{16}=2.66\ \ |:1.33\implies O:2\\\\\implies F.M.:C_2H_5NO_2\ \ (glicocol/glicina)$

$M_{C_2H_5NO_2}=(2{\cdot}12)+(5{\cdot}1)+14+(2{\cdot}16)=24+5+14+32=75\ g/mol$

Structura aminoacidului:

H₂C - COOH

    |

   NH₂