Question

care este cel mai mic și cel mai mare număr natural care,împărțit la 6 , da catul 43

Answer 1

 

$\displaystyle\bf\\D=?\\\^I=6\\C=43\\R\in\{0;~1;~2;~3;~4;~5\}\\\\D:6=43~Rest:~0~~\implies D=6\times43+0=258+0=258\\\\D:6=43~Rest:~1~~\implies D=6\times43+1=258+1=259\\\\D:6=43~Rest:~2~~\implies D=6\times43+2=258+2=260\\\\D:6=43~Rest:~3~~\implies D=6\times43+3=258+3=261\\\\D:6=43~Rest:~4~~\implies D=6\times43+4=258+4=262\\\\D:6=43~Rest:~5~~\implies D=6\times43+5=258+5=263\\\\D\in\{258;~259;~260;~261;~262;~263\}\\\\Cel~mai~mic~deimpartit~=~258\\\\Cel~mai~mmare~deimpartit~=~263$