Question

Care este concentratia procentuala a unei solutii de 500 de grame clorura de magneziu in care se gasesc 6,023* 10 la puterea 23 ioni de clorura?

Answer 1

MgCl2 = clorura de magneziu

miu = 24+35,5x2 = 95 g/mol

1 mol ..... 95 g ..... 2x6,022x10la23 ioni Cl

=>

95 g MgCl2 ................. 2x6,022x10la23 ioni Cl

a g MgCl2 ................... 6,022x10la23 ioni Cl

=> a = 47,5g MgCl2 = md

c% = mdx100/ms

= 47,5x100/500 = 9,5%