Question

Care este formula moleculara a substantei organice gazoase ce contine 40% c, 6,67h ,55,33o si densitatea de 2,44g/l la 2 atm si 27 grade celsius?

Answer 1

C : 40%      | :12 = 3,33    | : 3.33 = 1
H :6,67%    | : 1 = 6,67      | :3,33 = 2
O :53,33%  | :16 = 3,33    | : 3,33 =  1 ⇒ f. bruta CH2O
PV = nRT = m/M ·RT ⇒PM = qRT    M = 2,44·0,082·300/2 = 30 g/mol
(12+2+16)·n = 30     n = 1    f. moleculara : CH2O    CH2=O