Question

care este lungimea lui [ B D ] daca B( -2 ,4) si D( 2,6 )​

Answer 1

$\it BD^2=(x_D-x_B)^2+(y_D-y_B)^2=(2+2)^2+(6-4)^2=4^2+2^2=16+4=20\\ \\ BD=\sqrt{20}=\sqrt{4\cdot5}=2\sqrt5$