Question

care este numarul de moli(n ) si numarul de molecule care se gasesc in 32 gr de soda caustică ​

Answer 1

Răspuns:

Explicație:

MNaOH = 23 +16 +1=40-------> 40g/moli

n= 32 g : 40g/moli=0,8 moli NaOH

1mol NaOH------------6,023.10 ²³molecule

0,8 moli-------------------------x

x= 0,8  . 6,023.10²³molecule NaOH

MO2= 2.16=32--------> 32g/moli

MCaO= 40 +16=56-------> 56g/moli

MCa(NO3 )2= 40 + 2.14 + 6.16=164-------> 164g/moli

MHCl= 1 + 35, 5= 36,5-------> 36,5 g/moli

M AgNO3= 108 + 14 + 3.16=

M CuSO4= 64 + 32 + 4.16=

MNaOH= 23 +16 +1=40------>40g/moli

MAl2O3= 2,27 + 3.16=

MFe(OH )3= 56 + 3.16 +3=

MMg3 (PO4)2= 3. 24 + 2.31 + 8.16=

MHNO3= 1 + 14 + 3.16=63------> 63g/moli

MAl2 (SO4 )3= 2.27 + 3.32 + 12.16=342-------> 342g/moli

{am lasat cateva sa le calculezi }