Question

Care este procentu de O ( oxigen) din molecula de trioxid de sulf So3
Dau 20 de puncte

Answer 1

$M_{S O_{3} } = A_{S} +3 A_{O}=32+3*16=80.$

$80~ SO_{3} ............48~O \\ 100~SO3..........x~O \\ ---------- \\ x= \frac{100*48}{80}= 60$
 (%).

Answer 2

Masa moleculara SO3=Masa atomica S+3×Masa atomicaO=32+3×16=32+48=80 Masa moleculara 80gSO3.....32gS....48gO 100'/,....xla suta S....yla suta O X=32×100 supra 80= 3200:80 Y=48×100supra 80=4800:80