Question

care ma ajuta sa i dea dmnz sanatate

Answer 1

Explicație pas cu pas:

$- {x}^{2} - 2x + 3 \leqslant 0 \\ {x}^{2} + 2x - 3 \geqslant 0$

rezolvăm ecuația:

${x}^{2} + 2x - 3 = 0$

$\Delta = 4 + 12 = 16$

$x_{1} = \dfrac{ - 2 - \sqrt{16} }{2} = \dfrac{ - 2 - 4}{2} = - \dfrac{6}{2} = - 3 \\ x_{1} = \dfrac{ - 2 + \sqrt{16} }{2} = \dfrac{ - 2 + 4}{2} = \dfrac{2}{2} = 1$

$(x + 3)(x - 1) \geqslant 0$

$\implies x \in \Big(-\infty ; - 3\Big] \cup \Big[1; +\infty \Big)$