Question

care poate sa ma ajute repede?​

Answer 1

1.

(5 2) (5 2) (25+6 10-10) (31 0)

(3 -5) (3 -5) = (15-15 6+25) = (0 31)

2. TrA=5-5=0

3.

|5-x 2|

|3 -5-x| = -(5-x)(5+x)-6=0

-25+x^2-6=0

x^2=31 => x= radical din 31 sau x= - radical din 31

4.

detA=-25-6=-31

A^2=(31 0)=31 (1 0) =-(-31)*I2=-detA*I2

(0 31) (0 1)

5.

A^3=A^2*A=-detA*I2*A=-detA*A=31A

6.

(31 0) + (5 2) = (36 2)

(0 31) + (3 -5) (3 26)