Question

care sunt cei 11 izomeri de constituţie aciclici, fără enoli, corespund formulei moleculare C4H8O? ​

Answer 1

CH2=CH-CH2-CH2-OH    

CH2=CH-CH(OH)-CH3

CH3-CH2-CH2-CH=O

(CH3)2-CH2-CH=O

CH3-(CH3)CH-CH=O

CH3-CO-CH2-CH3

CH2=CH-O-CH2-CH3    

CH2=CH-CH2-O-CH3  

CH3-CH=CH-O-CH3

Answer 2

Răspuns:

alcooli nesaturati :

CH2=CH-CH2-CH2-OH    

CH2=CH-CH(OH)-CH3

derivati carbonilici:

CH3-CH2-CH2-CH=O;

(CH3)2-CH2-CH=O;

CH3-(CH3)CH-CH=O;  

CH3-CO-CH2-CH3

eteri :

CH2=CH-O-CH2-CH3    

CH2=CH-CH2-O-CH3  

CH3-CH=CH-O-CH3

Explicație: