Question

care va fi temperatura finala a unui obiect metalic cu temp. Initiala de 30grade celsius si capacitatea calorica de 2500 J/K daca primeste caldura de 5KJ

Answer 1

$Q_p=5000~J \\ \\ C=2500~J/K \\ \\ \Delta \theta =\frac{Q_p}{C}=2~K \\ \\ \theta_0=30~°C=303.15~K \\ \\ \theta =303.15+2=305.15~K$