Question

Cat da aceasta limita?Mie imi da +infinit si in barem le da 1/2...$\lim_{n \to \ 1} \frac{ ln(x+1)- ln2 }{x-1}$

Answer 1

$\lim_{n \to \ 1 \frac{ln(x+1)-ln2}{x-1}= \frac{0}{0}=ned$

Aplicam L`Hospital

[tex]\lim_{n \to \ 1 \frac{(ln(x+1)-ln2)`}{(x-1)`}= \lim_{n \to \ 1 \frac{1}{x+1}= \frac{1}{1+1}= \frac{1}{2} [/tex]