Question

Cât e log2(x+2)-log2(x+1)=1

Answer 1

Am atasat rezolvarea

Answer 2

$\log _2\left(x+2\right)-\log _2\left(x+1\right)=1 \\ \log _2\left(x+2\right)-\log _2\left(x+1\right)+\log _2\left(x+1\right)=1+\log _2\left(x+1\right) \\ \log _2\left(x+2\right)=1+\log _2\left(x+1\right) \\ \log _2\left(x+2\right)=\log _2\left(2\right)+\log _2\left(x+1\right) \\ \log _2\left(x+2\right)=\log _2\left(2\left(x+1\right)\right) \\ x+2=2\left(x+1\right) \\ x+2=2x+2 \\ x=2x=\ \textgreater \ x=0$