Question

cat e radical din 28

Answer 1

$\sqrt{28}=\sqrt{2^2\cdot7}=\sqrt{2^2}\cdot\sqrt{7}=2\sqrt7$

Answer 2

[tex] \sqrt{28} = \sqrt{2^2} * \sqrt{7} = 2 \sqrt{7} V: 2 \sqrt{7} = \sqrt{2^2*7} = \sqrt{4*7} = \sqrt{28} [/tex]