Question

cat e radical din 32​

Answer 1

$\sqrt{32} = \\ \\ \sqrt{2 \times 2 \times 2 \times 2 \times 2} = \\ \\ \sqrt{(2 \times 2) \times (2 \times 2) \times 2} = \\ \\ \sqrt{ {2}^{2} \times {2}^{2} \times 2 } = \\ \\ (2 \times 2) \sqrt{2} = \\ \\ 4 \sqrt{2}$

Answer 2

$\sqrt{32} = \sqrt{4^{2}*2 } =4\sqrt{2}$