Question

Cat este 2x la a doua - 4x - 10 = 0

Answer 1

$2x^2-4x-10=0 \\ a=2,b=-4,c=-10$
Δ $=b^2-4ac=4^2-4 \cdot 2 \cdot (-10)=16+80=96\ \textgreater \ 0$
$\displaystyle x_1= \frac{4+ \sqrt{96} }{2 \cdot 2} = \frac{4+4 \sqrt{6} }{4} = \frac{4(1+ \sqrt{6} )}{4} =1+ \sqrt{6} \\ \\ x_2= \frac{4- \sqrt{96} }{2 \cdot 2} = \frac{4-4 \sqrt{6} }{4} = \frac{4(1- \sqrt{6}) }{4} =1- \sqrt{6}$