Question

cat este 3 supra radical din 6

Answer 1

$^{^{^{\displaystyle{\sqrt{6}})}}}\dfrac{3}{\sqrt{6}}= \dfrac{3\sqrt{6}}{\sqrt{6}\cdot \sqrt{6}} = \\ \\ = \dfrac{3\sqrt{6}}{6}\,\,\,^{^{^{^{\displaystyle{(3}}}}}= \dfrac{\sqrt{6}}{2}$