Question

cat este lim x->infinit din x*radical din (x-1)/(x+1)

Answer 1

Salut,

$\lim\limits_{x\to +\infty}x\cdot\sqrt{\dfrac{x-1}{x+1}}=\lim\limits_{x\to +\infty}x\cdot\sqrt{\dfrac{1-\dfrac{1}x}{1+\dfrac{1}x}}=+\infty\cdot\sqrt{\dfrac{1-0}{1+0}}=+\infty\cdot 1=+\infty.$

Green eyes.