Question

cat este logaritm cu baza radical de ordin 3 din 2 din 8?

Answer 1

[tex]log_{ \sqrt[3]{2} }8= \frac{log_{2 }8}{log_{ 2 }\sqrt[3]{2}} =\frac{log_{2 }2^3}{log_{ 2 }2^{ \frac{1}{3} }} =\\ = \frac{3}{ \frac{1}{3} } =3: \frac{1}{3}=9[/tex]

Answer 2

$\displaystyle log_{ \sqrt[3]{2} }8= \frac{1}{ \frac{1}{3} }log_28=3log_28=3log_22^3=3 \cdot 3log_22=3 \cdot 3=9$