Question

Cat fac 2×[39÷(16-12÷4)+(9+6÷3)×7]

Answer 1

12/4 egal cu 3 6/3 egal cu 2 atunci

2x[39/(16-3)+(9+2)x7]

2x[39/13+11x7]

2x(3+77)

2x80 egal cu 160

Answer 2

2 x [ 39 : ( 16 -12 : 4 ) + ( 9 + 6 : 3) x 7 ] =

2 x [ 39 : ( 16 - 3 ) + ( 9+ 6 : 3 ) x 7 ]=

2 x( 39 : ( 16 : 3 ) + ( 9 +2 ) x 7 =

2 x ( 39 : 13 +11 x 7) =

2 x ( 3 +77) =

2 x 80=

160