Question

cat fac 5√48 + 3√50
si 3 √192 - 2√162

Answer 1

[tex]a=5\sqrt{48}+3\sqrt{50}\\ a=5\cdot4\sqrt3+3\cdot5\sqrt2\\ a=20\sqrt3+15\sqrt2=5(4\sqrt3+3\sqrt2)\\ b=3\sqrt{192}-2\sqrt{162}\\ b=3\cdot8\sqrt3-2\cdot9\sqrt2\\ b=24\sqrt3-18\sqrt2=6(4\sqrt3-3\sqrt2)[/tex]