Question

cât face 2√3·{√3-√2·[2√6-√3·(2√2+√3)]}

Answer 1

2√3·{√3-√2·[2√6-√3·(2√2+√3)]}=
2√3{√3-√2[2√6-2√6-3]}=
2√3{√3-√2*(-3)}=
2√3{√3+3√2}=
6+6√6=6(1+√6)

Answer 2

=2√3[√3-√2(2√6-2√6+3)]=2√3(√3-3√2)=2•3-6√6=6-6√6