Question

Cat face 5-5[(radical din 6+radical din 3)÷radical din 3- radical din 2]

Answer 1

5 - 5 [(radical 6 + radical 3) : radical 3 - radical 2] =

= 5 - 5 * [radical 3 * (radical 2 + 1) :  radical 3 - radical 2] =

= 5 - 5 * (radical 2 + 1 - radical 2) =

= 5 - 5 * 1 =

= 5 - 5 =

= 0