Question

cat face

a)1 supra 2 +1 supra 3 - 1 supra 6

b) (1 supra 4) +( 5 supra 35) : 7 supra 6

c) - 7 supra 12 : ( -14 supra 9 ) + ( - 1 supra 2 ) la puterea 3

Answer 1

$a) \\ \\ \frac{1}{2} + \frac{1}{3} - \frac{1}{6} = \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} - \frac{1}{6} = \frac{3}{6} + \frac{2}{6} - \frac{1}{6} = \frac{3 + 2 - 1}{6} = \frac{4}{6} = \frac{2}{3}$

$b) \\ \\ ( \frac{1}{4}) + ( \frac{5}{35}) : \frac{7}{6} = \frac{1}{4} + \frac{1}{7} : \frac{7}{6} = \frac{1}{4} + \frac{1}{7} \times \frac{6}{7} = \frac{1}{4} + \frac{1 \times 6}{6 \times 7} = \frac{1}{4} + \frac{6}{49} = \frac{73}{196}$

$c) \\ \\ - \frac{7}{12} : ( - \frac{14}{9}) + ( - \frac{1}{2}) ^{3} = - \frac{7}{12} : - \frac{14}{9} - \frac{1}{ {2}^{3} } = - \frac{7}{12} : - \frac{14}{9} - \frac{1}{8} = - \frac{7}{12} \times \frac{9}{ - 14} - \frac{1}{8} = - \frac{7 \times 9}{12 \times - 14} - \frac{1}{8} = - \frac{63}{ - 168} - \frac{1}{8} = - ( - \frac{63}{168}) - \frac{1}{8} = - ( - \frac{3}{8}) - \frac{1}{8} = \frac{3}{8} - \frac{1}{8} = \frac{2}{8} = \frac{1}{4}$