Question

cat face log in baza 2 din 11?

Answer 1

[tex]\displaystyle \\ \texttt{Aplicam formulele: } \\ log_a b = log_a 10 \times log_{10} b~~~~~(schimbare ~de ~baza) \\ \\ log_a b = \frac{1}{log_b a} \\ \\ Rezolvare: \\ log_{_2}11= log_{_2}10 \times log_{_{10}}11 = \frac{log_{_{10}}11}{log_{_{10}}2} = \frac{1,041}{0,301}= \boxed{3,45}[/tex]