Question

Cat oxid de magneziu se obtine prin arderea a 48 grame de Mg? cat oxigen se consuma? exprimati rezultatele in grame si moli

Answer 1

48 g a moli b moli

2Mg + O2 => 2MgO

2x24 1 2

=> a = 48 x 1 / 2x24 = 1 mol Mg

=> b = 48x2 / 2x24 = 2 moli MgO

n = nr moli = mada subst. / M. molec

=> masa Mg = 1 x 24 = 24 g

=> masa MgO = 2 x 40 = 80 g