Question

Cât se poate de explicit. Mulțumesc.

Answer 1

2*. practic : 2,025t HCN
teoretic : 202,5/75 = 2,7t = 2700kg HCn

n = m/M = 2700/27 = 100 kmoli HCN

CH4 + NH3 + 3/2O2 => HCN + 3H2O

1,5×22,4 m3 O2............1 kmol HCN
x m3..........................100 kmoli

x = 3360m^3 O2

Vaer (20%O2) = 5×VO2 = 16800m^3

3* MCH4 = 16g/mol , MC2H6 = 30g/mol

x - CH4 , y-C2H6

20/100×16x+80/100×30y = m

3,2x + 24y = m => m = 99,2x

x/y = 1/4 = > y = 4x


%CH4 = 3,2/99,2×100 = 3,2258
%C2H6 = 30/31×100 = 96,77