Question

cata apa trebuie adaugata la 360g saramura (c1=75) pentru a obtine o concentratie de 50%

Answer 1

$c1= \frac{md}{ms1} *100 =\ \textgreater \ md= \frac{c1*ms1}{100} =\ \textgreater \ md= \frac{75*360}{100} =270 [tex]c2= \frac{md}{ms2} *100 =\ \textgreater \ ms2= \frac{md*100}{c2} =\ \textgreater \ ms2= \frac{270*100}{50} =\ \textgreater \ ms2=540$
m apa1= ms1-md=360-270=90g apa
m apa2=ms2-md=540-270=270g apa
m apa adaugata= m apa2- m apa1=270-90=180 g apa