Question

cate game de HCl sunt necesare p/u a neutraliza 1,5 mol Mg(OH)2

Answer 1

Răspuns:

MMg(OH)2=24+2×16+2×1=58g/mol

MHCl=1+35,5=36,5g/mol

n=m/M

m=nxM=1,5×58=87gMg(OH)2

58g.............2x36,5g

Mg(OH)2 + 2HCl => MgCl2 + 2H2O

87g..................xg

x=87×2×36,5/58=calculează