Question

Cate grame de clorura de mangan sunt necesare pentru a prepara 500g solutie 20% ?


Datele problemei


ms=500 g sol MnCl2


c=20%


md=?


Formule de calcul necesare :


$c=\frac{md}{ms} *100$

md=c*ms/100


md=20*500/100=100g MnCl2

Answer 1

Răspuns:

ms=500g

C=20%

md=?

md=C×ms/100=20×500/100=100gMnCl2