Question

Cate grame de Fe2O3 rezulta la arderea a 112 g fier si cati moli de oxigen se consuma ?
E URGEEENT

Answer 1

4Fe + 3O₂ ⇒ 2Fe₂O₃

4*56g Fe.......................2*160g Fe₂O₃
112g Fe................................xg Fe₂O₃

x = (2*160*112)/(4*56) = 160g Fe₂O₃

4*56g Fe...................3 moli O₂
112g Fe.....................x moli O₂

x = (3*112)/(4*56) = 1,5 moli O₂